2x^2+33x-5.3=0

Solution for 2x^2+33x-5.3=0 equation:

2x^2+33x-5.3=0

a = 2; b = 33; c = -5.3;
Δ = b2-4ac
Δ = 332-4·2·(-5.3)
Δ = 1131.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1131.4}}{2*2}=\frac{-33-\sqrt{1131.4}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1131.4}}{2*2}=\frac{-33+\sqrt{1131.4}}{4}
$